因式分解 (1) m^4+64m (2) a^2b+ab+1+a (3) a^2+ac-bc-b^2 (4) 已知a+b=1,ab=-1求(1) a^2+b^2 (2) a^3+
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m^4+64m
=m(m³+64)
=m(m+4)(m²-4m+16)
(2) a^2b+ab+1+a
=ab(a+1)+(a+1)
=(a+1)(ab+1)
(3) a^2+ac-bc-b^2
=(a-b)(a+b)+c(a-b)
=(a-b)(a+b+c)
已知a+b=1,ab=-1求(1) a^2+b^2 (2) a^3+b³
a²+b²
=a²+2ab+b²-2ab
=(a+b)²-2ab
=1²-2×(-1)
=1+2
=3
a³+b³
=(a+b)(a²-ab+b²)
=(a+b)[(a²+2ab+b²-3ab)
=(a+b)[(a+b)²-3ab]
=1×(1+3)
=4
=m(m³+64)
=m(m+4)(m²-4m+16)
(2) a^2b+ab+1+a
=ab(a+1)+(a+1)
=(a+1)(ab+1)
(3) a^2+ac-bc-b^2
=(a-b)(a+b)+c(a-b)
=(a-b)(a+b+c)
已知a+b=1,ab=-1求(1) a^2+b^2 (2) a^3+b³
a²+b²
=a²+2ab+b²-2ab
=(a+b)²-2ab
=1²-2×(-1)
=1+2
=3
a³+b³
=(a+b)(a²-ab+b²)
=(a+b)[(a²+2ab+b²-3ab)
=(a+b)[(a+b)²-3ab]
=1×(1+3)
=4
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(1)
m^4+64m
= m(m^3+4^3)
= m(m+4)(m^2-4m+16)
(2)
a^2b+ab+1+a
= ab(a+1)+(a+1)
= (a+1)(ab+1)
(3)
a^2+ac-bc-b^2
= a^2-b^2+ac-bc
= (a+b)(a-b)+c(a-b)
= (a-b)(a+b+c)
(4)-(1)
a^2+b^2
= a^2 + 2ab +b^2 - 2ab
= (a+b)^2 -2ab
= 1^2 - 2*(-1)
= 1 +2
= 3
(4)-(2) 题目不完整
m^4+64m
= m(m^3+4^3)
= m(m+4)(m^2-4m+16)
(2)
a^2b+ab+1+a
= ab(a+1)+(a+1)
= (a+1)(ab+1)
(3)
a^2+ac-bc-b^2
= a^2-b^2+ac-bc
= (a+b)(a-b)+c(a-b)
= (a-b)(a+b+c)
(4)-(1)
a^2+b^2
= a^2 + 2ab +b^2 - 2ab
= (a+b)^2 -2ab
= 1^2 - 2*(-1)
= 1 +2
= 3
(4)-(2) 题目不完整
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(1)m^4+64m=m(m³+64)=m(m+4)(m²-4m+16)
(2)a²b+ab+1+a=ab(a+1)+(a+1)=(ab+1)(a+1)
(3)a²+ac-bc-b²=a²-b²+c(a-b)=(a+b)(a-b)+c(a-b)=(a+b+c)(a-b)
(4)1、a²+b²=(a+b)²-2ab=1²-2×(-1)=3
2、a³+b³=(a+b)(a²-ab+b²)=a²+b²-ab=3-(-1)=4
(2)a²b+ab+1+a=ab(a+1)+(a+1)=(ab+1)(a+1)
(3)a²+ac-bc-b²=a²-b²+c(a-b)=(a+b)(a-b)+c(a-b)=(a+b+c)(a-b)
(4)1、a²+b²=(a+b)²-2ab=1²-2×(-1)=3
2、a³+b³=(a+b)(a²-ab+b²)=a²+b²-ab=3-(-1)=4
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