Question

数学题：已知x^2-4xy+4y^2=0,那么(x-y)/（x+y）的值等于？求步骤，答案是1/3.

Answer 1

x^2-4xy+4y^2=0
即(x-2y)²=0
所以x-2y=0
故x=2y
所以(x-y)/（x+y）
=(2y-y)/(2y+y)
=y/3y
=1/3

Answer 2

原式变为(x-2y)^2=0
所以x=2y
那么(x-y)/(x+y)=y/3y
=1/3
原式变为(x-2y)^2=0
所以x=2y
那么(x-y)/(x+y)=y/3y
=1/3

Answer 3

懂了、、、 X2是X的平凡啊
X2-4XY+4Y2=0
(X-2Y)2=0
x-2Y=0
X=2Y
所以
X-Y/X+Y

2Y-Y/2Y+Y=1/3

希望采纳

Answer 4

x^2-4xy+4y^2=0 ==> (x-2y)^2 =0 ==> x = 2y (x-y) / (x+y) = (2y -y) / (2y +y) = y / 3y = 1/3

Answer 5

因为X＾2－4XY＋4Y＾2＝0即（X－2Y）＾2＝0．．所以X＝2Y。由此代入问题中可以求出答案是1/3

Answer 6

原方程化简(x-2y)^2=0 x=2y原式=y/3y=1/3