Question

(a+1)²(a-1)²-(a+2)²(a-2)²

Answer 1

(a+1)²(a-1)²-(a+2)²(a-2)²
=[(a+1)(a-1)]²-[(a+2)(a-2)]²
=(a²-1)²-(a²-4)²
=(a²-1+a²-4)(a²-1-a²+4)
=3(2a²-5)
=6a²-15

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Answer 2

(a+1)²(a-1)²-(a+2)²(a-2)²
=(a^2-1)^2-(a^2-4)^2
=a^4-2a^2+1-(a^4-8a^2+16)
=a^4-2a^2+1-a^4+8a^2-16
=6a^2-15

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Answer 3

(a+1)²(a-1)²-(a+2)²(a-2)²

=(a²-1)²-(a²-4)²
=a^4-2a²+1-(a^4-8a²+16)=6a²-15

Answer 4

=(a²-1)²-(a²-4)²
=(a²-1+a²-4)(a²-1-a²+4)
=3(2a²-5)
=6a²-15

Answer 5

原式=[(a+1)(a-1)]²-[(a+2)(a-2)]²
=(a²-1)²-(a²-4)²
=[(a²-1)+(a²-4)][(a²-1)-(a²-4)]
=3(2a²-5)
=6a²-15