Question

hibernate验证用户登录时用户名和密码

用hibernate验证用户名和密码，在adminDAOImpl中总会提示找不到criteria这个类，但是明明导入了。上图，有代码，错误信息。求高人指点。
public class AdminLogIn extends ActionSupport {
private Admin adminBean;
//private AdminDAOImpl ad = new AdminDAOImpl();
public Admin getAdminBean() {
return adminBean;
}
public void setAdminBean(Admin adminBean) {
this.adminBean = adminBean;
}
public String execute() {
AdminDAOImpl ad = new AdminDAOImpl();
if(ad.isValidAdmin(adminBean.getAdminName(), adminBean.getAdminPassword()))
return SUCCESS;
else
{
adminBean.setAdminName("");
adminBean.setAdminPassword("");
return ERROR;
}
}
}

public class AdminDAOImpl implements AdminDAO {
public AdminDAOImpl() {};
public boolean isValidAdmin(String adminName, String adminPassword) {
Session s = null;
Admin admin;
try {
s = HibernateUtil.getSessionFactory().getCurrentSession();
Criteria c = s.createCriteria(Admin.class);
c.add(Restrictions.eq("adminName", "bochao"));
admin =(Admin) c.uniqueResult();
} finally {
if (s != null)
s.close();
}
if(admin == null)
return true;
else
return false;
}
}

错误信息

Struts Problem Report
Struts has detected an unhandled exception:
Messages:org.hibernate.criterion.Criterion org/hibernate/criterion/Criterion File:org/apache/catalina/loader/WebappClassLoader.javaLine number:1,711

Answer 1

admin =(Admin)s.createCriteria(Admin.class).add(Restrictions.eq("adminName","bochao")).uniqueResult();先这样写吧，你的错误信息太少了。多贴点信息上来吧。

Answer 2

有没有更全的异常信息？