Question

化简:(x²-4x+4分之x²-4)-(x+2分之x-2)除x-2分之x再任选一个你喜欢的数代入求值 急急

急急急！！！！！

Answer 1

很高兴为您解答：
(x²-4X+4分之x²-4+x+2分之2-x)除以x-2分之x

[(x²-4)/（x²-4x+4)+(2-x)/(x+2)]÷[x/(x-2)]
=[(x-2)(x+2)/(x-2)²+(2-x)/(x+2）]×(x-2)/x
=[(x+2)/(x-2)+(2-x)/(x+2)]×(x-2)/x
={[(x+2)²-(x-2)²]/(x²-4)}×(x-2)/x
=8x/[(x-2)(x+2)]*(x-2)/x

=8/(x+2)
当x=2时，原式=2
谢谢，有帮助记得采纳哦。
不懂欢迎追问。

追问

=[(x-2)(x+2)/(x-2)²+(2-x)/(x+2）]×(x-2)/x ?

={[(x+2)²-(x-2)²]/(x²-4)}×(x-2)/x ?

=8x/[(x-2)(x+2)]*(x-2)/x ?

追答

原式={(x+2)/(x-2)+(2-x)/(x+2)}x(x-2)/x
=（x+2）\x-(x-2)^2/x(x+2)
= 8x/x(x+2)==8/(x+2)

追问

还是不懂
原式={(x+2)/(x-2)+(2-x)/(x+2)}x(x-2)/x
=（x+2）\x-(x-2)^2/x(x+2)
= 8x/x(x+2)==8/(x+2)

是什么的

追答

哪一步不懂

追问

原式={(x+2)/(x-2)+(2-x)/(x+2)}x(x-2)/x
=（x+2）\x-(x-2)^2/x(x+2)
= 8x/x(x+2)==8/(x+2)
是解释哪的

追答

[(x-2)(x+2)/(x-2)²+(2-x)/(x+2）]×(x-2)/x 这个

追问

那
={[(x+2)²-(x-2)²]/(x²-4)}×(x-2)/x ?

=8x/[(x-2)(x+2)]*(x-2)/x ?
呢

追答

={[(x+2)²-(x-2)²]/(x²-4)}×(x-2)/x =8x/[(x-2)(x+2)]*(x-2)/x =8/(x+2)
=8x/[(x-2)(x+2)]*(x-2)/x=8/(x+2)
都等于8/(x+2)。