Question

(x-1)²/x²-1+x²/x+1化简

Answer 1

(x-1)²/(x²-1)+x²/(x+1)
=(x-1)²/[(x+1)(x-1)]+x²/(x+1)
=(x-1)/(x+1)+x²/(x+1)
=(x²+x-1)/(x+1)

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追问

若x²-2=0,只是多少？谢谢

追答

x²-2=0
x²=2
x=±根号2

追问

如果化简求值呢？答案是1

追答

(x²+x-1)/(x+1)

=[(x²-2)+(x+1)]/(x+1)
=[0+(x+1)]/(x+1)
=(x+1)/(x+1)
=1