Question

已知x^2+y^2-2x+6y+10=0

求x^2008-1/y的值

Answer 1

很高兴为您回答;
x^2+y^2-2x+6y+10=0
x²-2x+1+y²+6y+9=0
(x-1)²+(y+3)²=0
∴(x-1)=0 (y+3)²=0
x=1 y=- 3
x^2008-1/y
=1+1/3
=4/3
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Answer 2

x²+y²-2x+6y+10=0
x²-2x+1+y²+6y+9=0
(x-1)²+(y+3)²=0
x-1=0 y+3=0
∴x=1 y=-3
∴(x^2008-1)/y
=(1^2008-1)/(-3)
=(1-1)/(-3)
=0

Answer 3

x^2+y^2-2x+6y+10=0
(x-1)^2+(y+3)^2=0
x-1=0 y+3=0
x=1 y=-3
x^2008-1/y
=1+1/3
=4/3

Answer 4

x^2+y^2-2x+6y+10=0
(x-1)^2+(y+3)^2=0
x-1=0, y+3=0
x=1,y=-3
x^2008-1/y
=1+1/3
=4/3