Question

分解因式:1-a2+ab-1/4b2

o(︶︿︶)o 唉

Answer 1

1-a2+ab-1/4b2
1-a²+ab-1/4b²
=1-(a²-ab+1/4b²)
=1-(a-1/2b)²
=[1+(a-1/2b)][1-(a-1/2b)]
=(1+a-1/2b)(1-a+1/2b)

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Answer 2

最简分解法：
1-a2+ab-1/4b2

=1／4(4－4a²＋4ab－b²)
=1／4[4－(4a²－4ab＋b²)]
=1／4[4－(2a－b)²]
=1／4(2＋2a－b)(2－2a＋b)

Answer 3

1-a2+ab-1/4b2
=1-(a^2-2*a*(b/2)+(b/2)^2)
=1-(a-b/2)^2
=(1+a-b/2)(1-(a-b/2))
=(a-b/2+1)(1-a+b/2)

Answer 4

原式=-[(a²-ab+1/4b²)-1]
=-[(a-1/2b)²-1]
=-(a-1/2b+1)(a-1/2b-1)