Question

初二下数学两道约分的题，求大神详细解答，很急阿嘤 1-2x+x²分之x²-3x+2、

谢谢~
总共是两道题阿，~~~~(>_<)~~~~

Answer 1

x(x+3)(x-2)(x-1)/[x(1-x)(x+3)(x-2)]
=-1

追问

谢谢。。
那第一个呢？

追答

( 1-2x+x²)/(x²-3x+2)=(x-1)²/[(x-2)(x-1)]
=(x-1)/(x-2)

Answer 2

x(x+3)(x-2)(x-1)/[x(1-x)(x+3)(x-2)]
=-1

追问

...不要复制的

追答

=(x-1)/(x-2)

=x(x+3)(x-2)(x-1)/[x(1-x)(x+3)(x-2)]

=-1行了吧？~

Answer 3

原式=(x-1)/(x-2)
原式=x(x+3)(x-2)(x-1)/[x(1-x)(x+3)(x-2)]
=-1

Answer 4

这里只有1题