
展开全部
1、2005÷2003/2004
=(2003+2)×2004/2003
=2004+2×2004/2003
=2004+2×(1+1/2003)
=2006又1/2003
2、5/12×1/13+2/3÷13
=5/12×1/13+2/3×1/13
= 1/13×(5/12+8/12)
=1/13×13/12
=1/12
3、3/4×[(7/15-1/3)÷1/6]
=3/4×[(7/15-5/15)×6]
=3/4×6×2/15
=3/5
=(2003+2)×2004/2003
=2004+2×2004/2003
=2004+2×(1+1/2003)
=2006又1/2003
2、5/12×1/13+2/3÷13
=5/12×1/13+2/3×1/13
= 1/13×(5/12+8/12)
=1/13×13/12
=1/12
3、3/4×[(7/15-1/3)÷1/6]
=3/4×[(7/15-5/15)×6]
=3/4×6×2/15
=3/5
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询