1-(1-1/1-x)的平方/x的平方-x+1/x的平方-2x+1
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原式=1-[(1-x-1)/(1-x)]²*(x²-2x+1)/(x²-x+1)
=1-x²/(x-1)²*(x-1)²/(x²-x+1)
=1-x²/(x²-x+1)
=(x²-x+1-x²)/(x²-x+1)
=(1-x)/(x²-x+1)
=1-x²/(x-1)²*(x-1)²/(x²-x+1)
=1-x²/(x²-x+1)
=(x²-x+1-x²)/(x²-x+1)
=(1-x)/(x²-x+1)
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