Question

因式分解 a2-b2-4a+4b

因式分解 2x2+2x+0.5 a2-b2-4a+4b 20a2bx-456y2x 2代表平方给我解下谢谢啊

Answer 1

a2-b2-4a+4b
=(a+b)(a-b)-4(a-b)
=(a+b-4)(a-b)

2x2+2x+0.5
=1/2(4x²+4x+1)
=1/2(2x+1)²

20a2bx-456y2x （该题打字有误，请审核）

Answer 2

a2-b2-4a+4b=（a+b）（a-b）-4(a-b)=(a-b)(a+b-4) 2x2+2x+0.5 =2(x2+x+1/4)=2(x+1/2)2 20a2bx-456y2x =4x(5a2b-114y2)

Answer 3

a2-b2-4a+4b= (a+b)(a-b)-4(a-b)=(a+b-4)(a-b)就是这样啦