Question

用java实现： 把数组oldArr[] 1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5中不是0的元素存放在新数组newArr[]中

Answer 1

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
public class Change {
    public static void main(String args[]) {
        Integer[] oldArr = { 1, 3, 4, 5, 0, 0, 6, 6, 0, 5, 4, 7, 6, 7, 0, 5 };
        List<Integer> data = new ArrayList<Integer>();
        for (int i=0;i<16;i++) {
            if (oldArr[i] != 0) {
                data.add(oldArr[i]);
            }
        }
        Integer[] newArr = data.toArray(new Integer[0]);
                                                                                                             
    }
}

代码如上，以后可以继续交流java的相关编程

Answer 2

具体步骤如下：
public class Demo {
public static void main(String[] args) {
int j=0;
int oldArr[] = {1,3,4,5,0,0,6,6,0,5,4,7,6,7,0,5};
int newArr[] = null;
newArr = new int[oldArr.length];
for(int i = 0 ; i < oldArr.length ; i++) {
if(oldArr[i] != 0) {
newArr[j] = oldArr[i];
System.out.println("newArr["+j+"] = " + newArr[j]);
j++;
}
}
}
}

最简遍的办法，而且容易懂，速度采纳！

Answer 3

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

public class $ {
public static void main(String args[]) {

Integer[] oldArr = { 1, 3, 4, 5, 0, 0, 6, 6, 0, 5, 4, 7, 6, 7, 0, 5 };

List<Integer> data = new ArrayList<Integer>();

for (Integer em : oldArr) {
if (em != 0) {
data.add(em);
}
}
Integer[] newArr = data.toArray(new Integer[0]);

System.out.println(Arrays.deepToString(newArr));
}
}

结果
[1, 3, 4, 5, 6, 6, 5, 4, 7, 6, 7, 5]