VB中输出如下矩阵,如图,求代码
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sub xx()
dim i as integer,m as integer,StrA as String
for i = 1 to 4
for m = i to i + 3
If m Mod 4 <> 0 Then StrA = StrA & " " & m Mod 4 Else StrA = StrA & " " & 4
next m
stra = strA & Chr(10)
next
msgbox strA
end sub
dim i as integer,m as integer,StrA as String
for i = 1 to 4
for m = i to i + 3
If m Mod 4 <> 0 Then StrA = StrA & " " & m Mod 4 Else StrA = StrA & " " & 4
next m
stra = strA & Chr(10)
next
msgbox strA
end sub
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