Question

已知集合a＝｛x/x2－16＜0｝，b＝｛x/x2－4x＋3＝0｝，求a∪b和a∩b

Answer 1

解:A: x<-4或0<x<4 B: x<0或 1<x<3所以A∩B= {xlx<-4或1<x<3}A∪B={xlx<4且x≠0}

Answer 2

a = {x | -4 < x < 4}b = {x | x =1, 3} a∪b = {x | -4 < x < 4}a∩b = {x | x =1, 3}