Question

解不等式（x-5）/（x²-2x-3）≥1

Answer 1

||是或的意思

追问

额，没有过程诶，我想知道是怎么做的。

追答

Reduce[expr,vars]
reduces the statement expr by solving equations or inequalities for vars and eliminating quantifiers.

摘自http://reference.wolfram.com/mathematica/ref/Reduce.html

Answer 2

x2－2－3≤x－5 x2－3x＋2≥0 （x－1）(x－2)≥0 得到x≥2