Question

用SQL查询出每门成绩都大于80分的学生姓名

Answer 1

代码如下：

1. select name from stu where name not in(
   

2. select name from stu where
   

3. fenshu<=80 group by name having
   

4. count(*)>=1) group by name

5. 先查到任何一门不足80的学生，再排除这些学生。

select name from stu group by name having min(fs)>=80。

还有这些简单语句。

简单基本的sql语句

更新：update table1 set field1=value1 where 范围

查找：select * from table1 where field1 like ’%value1%’ （所有包含‘value1’这个模式的字符串）

排序：select * from table1 order by field1,field2 [desc]

求和：select sum(field1) as sumvalue from table1

平均：select avg(field1) as avgvalue from table1

最大：select max(field1) as maxvalue from table1

最小：select min(field1) as minvalue from table1[separator]

Answer 2

select name from student where stu_id not in(select distinct stu_id from score where grade < 80)

Answer 3

select * from 数据表 where 字段>80;