Question

计算：三角函数！（sin19°+cos199°/sin341°-cos161°）+（tan18°+cos34°tan162°-cos198°）

（sin19°+cos199°/sin341°-cos161°）+（tan18°+cos34°/tan162°-cos198°）
题目有错
正确应为：(sin19°+cos199° )/(sin341°-cos161°)+( tan18°+cos342°)/( tan162°+cos198°)

Answer 1

题中有误
(sin19°+cos199° )/(sin341°-cos161°)+( tan18°+cos342°)/( tan162°+cos198°)
=(sin19°+cos199° )/(sin(360-19°)-cos(360-199°))+( tan18°+cos(360-18°)/( tan(180-18°)+cos(180+18°)
=(sin19°+cos199° )/(-sin(19°)-cos(199°))+( tan18°+cos(18°)/( -tan(18°)-cos(18°)
=-1-1=-2

Answer 2

不应该是这样吧，弱弱问一下，题有木有抄错？

追问

抱歉：(sin19°+cos199° )/(sin341°-cos161°)+( tan18°+cos342°)/( tan162°+cos198°)

追答

好吧，没关系了