Question

化简(a-b+c)的平方乘(b-a-c)的四次方乘(a+c-b)乘(b-c-a)

Answer 1

(a-b+c)的平方乘(b-a-c)的四次方乘(a+c-b)乘(b-c-a)
=(a-b+c)²×(a-b+c)的4次幂×(a-b+c)×[-(a-b+c)]
=-(a-b+c)的8次幂

Answer 2

专任教师为你服务,
不懂之处,请讨论.
将个别算式提取﹣号。
(a-b+c)^2*(b-a-c)^4*(a+c-b)*(b-c-a)
=(a-b+c)^2*[-(a-b+c)]^4*(a-b+c)*[-(a-b+c)]
=(a-b+c)^2*(a-b+c)^4*(a-b+c)*[-(a-b+c)]
=-(a-b+c)^8