
因式分解:(x²+y²-z²)²-4x²y²
2个回答
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(x²+y²-z²)²-4x²y²
=(x²+y²-z²+2xy)(x²+y²-z²-2xy)
=[(x+y)²-z²][(x-y)²-z²]
=(x+y+z)(x+y-z)(x-y+z)(x-y-z)
=(x²+y²-z²+2xy)(x²+y²-z²-2xy)
=[(x+y)²-z²][(x-y)²-z²]
=(x+y+z)(x+y-z)(x-y+z)(x-y-z)
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