Question

题一:把多项式a^3-2a+a因式分解的结果是? 题二:分解因式:a-6ab+9ab^2=

Answer 1

题一:把多项式a^3-2a+a因式分解的结果是?
a^3-2a+a
解，得：
==a(a^2-2+1)
==a(a^2-1)
==a(a+1)(a-1)

题二:分解因式:
a-6ab+9ab^2
解，得：
==a(9b^2-6b+1)
==a(3b-1)^2

Answer 2

第一个题错,应该是-2a²吧?
a³-2a²+a
=a(a²-2a+1)
=a(a-1)²

a-6ab+9ab²
=a(9b²-6b+1)
=a(3b-1)²

Answer 3

a^3-2a^2+a
=a(a^2-2a+1)
=a(a-1)^2

a-6ab+9ab^2
=a(1-6b+9b^2)
=a(1-3b)^2

Answer 4

1、应该是a³-2a+1吧
a³-2a+a=a³-a²+a²-2a+1=a²（a-1）+（a-1）²=（a-1）（a²+a-1）
如果是原来就是a³-a=a（a+1）（a-1）

2、（3ab-1）²

Answer 5

a³-2a+a=a(a²-1）=a(a+1)(a-1)

a-6ab+9ab²=a(1-6b+9b²)=a(1-3b)²

Answer 6

a^3-2a+a=a^3-a=a(a^2-1)=a(a+1)(a-1)
a-6ab+9ab^2=a(1-6b+9b^2)=a(1-3b)^2