(a+b)(a-b)-(a-b)^2+2b^2,其中,a=2,b=-1/2
1个回答
2013-05-05
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1)
(a+b)(a-b)-(a-b)²+2b²
=(a-b)(a+b-a+b)+2b²
=2b(a-b)+2b²
=2b(a-b+b)
=2ab
=2×2×(-1/2)
=-2
2)
〔(-3xy)²x³-2x²(3xy)³1/2y〕/9x^4y^4
=〔(3xy)²x³-x²(3xy)³y〕/〔(3xy)²〕²
=〔x³-x²y(3xy)〕/(3xy)²
=x²〔x-y(3xy)〕/(9x²y²)
=(x-3xy²)/(9y²)
(a+b)(a-b)-(a-b)²+2b²
=(a-b)(a+b-a+b)+2b²
=2b(a-b)+2b²
=2b(a-b+b)
=2ab
=2×2×(-1/2)
=-2
2)
〔(-3xy)²x³-2x²(3xy)³1/2y〕/9x^4y^4
=〔(3xy)²x³-x²(3xy)³y〕/〔(3xy)²〕²
=〔x³-x²y(3xy)〕/(3xy)²
=x²〔x-y(3xy)〕/(9x²y²)
=(x-3xy²)/(9y²)
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