Question

求一个C语言的程序填空,请大神指教

将十进制整数转换成n进制。
main( )
{inti=0,base,n,____,num[20];
printf("Enterdatathatwillbeconverted\n");
scanf( "%d",&n)
printf("Enterbase \n")；
scanf( "%d",&base);
do
{i++;num[i]=_________;
n=_________;
}while(n!=0);
printf("The data %d has been converted into the %d——base data:\n",n,base);
for (__________)
printf("%d",num[j]);
}

Answer 1

main( )
{inti=0,base,n, j ,num[20];
printf("Enterdatathatwillbeconverted\n");
scanf( "%d",&n)
printf("Enterbase \n")；
scanf( "%d",&base);
do
{i++;num[i]= n%base;
n= n/base ;
}while(n!=0);
printf("The data %d has been converted into the %d——base data:\n",n,base);
for (j=i;j>0;j--)
printf("%d",num[j]);
}

追问

报错阿大神.. 不能运行..

追答

报什么错？

追问

追答

呵呵，是你拷贝过来的代码有问题，有些少空格。你这个是填空题，我只是帮你把空填了。

严格的代码如下：
#include
int main( )
{
int i=0,base,n, j ,num[20];
printf("Enter data that will be converted\n");
scanf( "%d",&n);
printf("Enterbase \n");
scanf( "%d",&base);
do
{
i++;
num[i] = n%base;
n = n/base ;
}while(n!=0);
printf("The data %d has been converted into the %d——base data:\n",n,base);
for (j=i;j>0;j--)
printf("%d",num[j]);
}