Question

用卡诺图化简逻辑函数成为最简与或式和最简或与式,求详细解法!!!重酬，五道题都需要解答！！

Answer 1

F=AB'+D'

F=A'B'+D'

F=A'B+AD

F=ABD'+CD'

F=C'D+B'D'

Answer 2

(1)F(A,B,C,D)= ∑m(0,2,4,6,8,9,10,11,12,14)
=∑m(0,2,4,6)+∑m(8,9,10,11)+∑m(9,11,13,15)
=A’D’+AB’+AD==>或与式F=(A+D’)(A+B’+D’)(A’+B’+D)

或=∑m(0,2,4,6)+∑m(0,2,8,10)+∑m(9,11,13,15)
=A’D’+B’D’+AD==>或与式F=(A+D’)(A+B’+D’)(A’+B’+D)

(2)F(A,B,C,D)= ∑m(5,7,9,11,13,15)
=∑m(5,7,13,15)+∑m(9,11,13,15)
=BD+AD==>或与式F=(A+B)(D)

(3)F(A,B,C,D)= ∑m(4,5,6,7,9,11,13,15)
=∑m(4,5,6,7)+∑m(9,11,13,15)
=A’B+AD==>或与式F=(A+B)(A’+D)(B+D)

(4)F(A,B,C,D)= ∑m(0,1,3,4,5,7,8,9,11,13,15)
=∑m(0,1,4,5)+ ∑m(0,1,8,9)+ ∑m(1,3,5,7,9,11,13,15)
=A’C’+B’C’+D==>或与式F=(A’+B’+D)(C’+D)

(5)F(A,B,C,D)= ∑m(0,1,2,5,8,9,10,13)
=∑m(0,2,8,10)+ ∑m(1,5,9,13)
=B’D’+C’D==>或与式F=(B’+C’)(B’+D)(C’+D’)