Question

求使1+2+3+4+5+……+n>100成立的最小自然数n的值,画出程序图

Answer 1

利用数列的知识就可以很容易解决了！首项是1，公差是1，则前n项和就是：（n+1)n/2>100可求出n的值！

Answer 2

Answer 3

#include<stdio.h>int main(){int n, N, sum = 0;for (n = 0; sum >100; n++){sum += n;}sum = sum - n + 1;N = n - 2; printf("sum = %d and N = %d\n",sum,N);return 0;}

Answer 4

数学书里有...