
先化解,再求值:2a+3/a²+1-a+3/a²+1×2a²+6a/a²+6a+9,其中a=根号2 5
2个回答
展开全部
2a+3/a²+1-a+3/a²+1×2a²+6a/a²+6a+9
=(2a+3-a-3)/(a^2+1)*2a(a+3)/(a+3)^2
=2a^2/(a^2+1)(a+3)
=4/(2+1)(根号2+3)
=4(根号2-3)/3
=(2a+3-a-3)/(a^2+1)*2a(a+3)/(a+3)^2
=2a^2/(a^2+1)(a+3)
=4/(2+1)(根号2+3)
=4(根号2-3)/3
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询