Question

化简代数式[(a^2+b^2)/(a^2-b^2)]/[2ab/(a-b)(a+b)^2]

Answer 1

=(a²+b²)/(a+b)(a-b) ×(a-b)(a+b)²/2ab
=(a+b)(a²+b²)/2ab

追问

p=(x^2)/(x-y)+(y^2)/(y-x),q=(x-y)^2+(x+y)小敏、小聪两人分别计算了p和q的值,p大还是q大，为什么，说明理由

追答

p=x²/(x-y)-y²/(x-y)
=(x²-y²)/(x-y)
=(x+y)
∵(x-y)²>=0
∴p<=Q

Answer 2

原式=(a²+b²)/(a+b)(a-b)*(a+b)²(a-b)/2ab
=(a²+b²)(a+b)/2ab
=(a³+a²b+ab²+b³)/2ab

追问

p=(x^2)/(x-y)+(y^2)/(y-x),q=(x-y)^2+(x+y)小敏、小聪两人分别计算了p和q的值,p大还是q大，为什么，说明理由

追答

爱娜我，重新问