{x+y/2+x-y/3=1,3(x+y)/2+x-y/3=17
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2013-05-10
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y-x²/(x-y)
=[(x+y)(x-y)-x²]/(x-y)
=(x²-y²-x²)/(x-y)
=y²/(y-x)
=[(x+y)(x-y)-x²]/(x-y)
=(x²-y²-x²)/(x-y)
=y²/(y-x)
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