Question

C语言，这个程序的错误？

#include <stdio.h>
void main()
{
int a[5];int temp;int a;int b;int il;
for(int i=0;i<5;i++)
scanf("%d",&a[i]);
for(a=0;a<5;a++)
{
for(b=0;b<5-a;b++)
{
if(a[b]>a[b+1])
{
temp=a[b];
a[b]=a[b+1];
a[b+1]=a[b];
}
}
}
for(il=0;i<5;il++)
printf("%d",il[il]);
}
There are no conversions to array types, although there are conversions to references or pointers to arrays
c:\users\administrator\desktop\my c project\冒泡，.cpp(7) : error C2446: '<' : no conversion from 'const int' to 'int *'
Conversion from integral type to pointer type requires reinterpret_cast, C-style cast or function-style cast
c:\users\administrator\desktop\my c project\冒泡，.cpp(7) : error C2040: '<' : 'int [5]' differs in levels of indirection from 'const int'
c:\users\administrator\desktop\my c project\冒泡，.cpp(7) : error C2105: '++' needs l-value
c:\users\administrator\desktop\my c project\冒泡，.cpp(9) : error C2113: pointer can only be subtracted from another pointer
c:\users\administrator\desktop\my c project\冒泡，.cpp(20) : error C2109: subscript requires array or pointer type

Answer 1

#include <stdio.h>
#include <stdlib.h>
int main()
{
    int a[5];
    int temp;
    int b;
    int c;
    int i;
    for(i=0;i<5;i++)
        scanf("%d",&a[i]);
       
    for(b=0;b<5-1;b++)
    {
        for(c=0;c<5-1;c++)
        {
            if(a[c]>a[c+1])
            {
                temp=a[c];
                a[c]=a[c+1];
                a[c+1]=temp;
            }
        }
    }
    for(i=0;i<5;i++)
        printf("%d",a[i]);
    system("pause");
    return 0;
}

Answer 2

太粗心了吧，先是变量i没定义，然后做交换的循环错误，大循环for(a=1；a＜5；a++)
for(b=0；b＜5-a；b++)

交换语句的第三句又错了，看看清楚谁和谁交换，还有相当无语，最后一句输出语句的数组名字也错了，，亲！你编的时候在干嘛！！

Answer 3

数组a和int a的名字一样了，不能这么起名。

Answer 4

temp=a[b];a[b]=a[b+1];a[b+1]=a[b]; 该句有问题 il数组没定义。等