Question

先化简（x-1/x+1+x的平方-2x+1/1)除以x-1/x

，然后选取一个你喜欢的值带入计算一下。

Answer 1

解：
（x-1/x+1+x²-2x+1/1)÷(x-1/x)
=(x-1/x+1+(x-1)²)/(x-1/x)
=x(1/(x+1)+(x-1))
=x(x²/(x+1))
=x³/(x+1)
选取x=1
原式=1/2

如仍有疑惑，欢迎追问。 祝：学习进步！

Answer 2

[(x+1)/(x-1)+1/(x²-2x+1)]÷x/(x-1)
=[(x+1)/(x-1)+1/(x-1)²]·(x-1)/x
=(x+1)/x+1/[x(x-1)]
=(x²-1+1)/[x(x-1)]
=x/(x-1)
取x=2
则原式=2
“/”前为分子，和为分母