已知x/y=3 ,x²-y²/xy÷2(x-y)²/xy-y²的值
2个回答
展开全部
原式 = (x + y)(x - y)/.xy ÷ 2(x - y)² / y(x - y)
= (x+ y)(x - y)/ xy × y(x - y)/2(x - y)²
= (x + y)/ 2 x
= x / 2 x + y / 2x
= 1 / 2 + 1 / 2(x / y)^ -1
当 x / y = 3 时,原式 = 1 / 2 + 1 / 2 × 3 ^ - 1
= 1 / 2 + 1 / 2 × 1 / 3
= 1 / 2 + 1 / 6
= 2 / 3
= (x+ y)(x - y)/ xy × y(x - y)/2(x - y)²
= (x + y)/ 2 x
= x / 2 x + y / 2x
= 1 / 2 + 1 / 2(x / y)^ -1
当 x / y = 3 时,原式 = 1 / 2 + 1 / 2 × 3 ^ - 1
= 1 / 2 + 1 / 2 × 1 / 3
= 1 / 2 + 1 / 6
= 2 / 3
本回答被提问者和网友采纳
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
展开全部
x²-y²/xy÷2(x-y)²/xy-y²
=(x-y)(x+y)/xy×y(x-y)/2(x-y)²
=(x+y)/2x
=(x/y+1)/(2x/y)
=(3+1)/(2×3)
=2/3
=(x-y)(x+y)/xy×y(x-y)/2(x-y)²
=(x+y)/2x
=(x/y+1)/(2x/y)
=(3+1)/(2×3)
=2/3
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询