Question

在△abc中，∠a=80°，∠abc和∠acbde平分线交于点o，则∠boc的度数是

Answer 1

解：∵OB平分∠ABC

           OC平分∠ACB

       ∴∠OBC=1/2∠ABC

          ∠OCB=1/2∠ACB

       又∵∠A=80°

       ∴∠ABC+∠ACB=100°

       ∴∠OBC+∠OCB=50°

       ∴∠BOC=130°

答：∠BOC的度数是130°