Question

c++，用递归法求平方和，即1*1+2*2+3*3。。。

我是这样写的：#include <iostream>
using namespace std;
int dst(int x)
{int y;<br> y=x*x;<br>return y;<br>}
int main ()
{int sum,a=1,n;<br> cin>>n;<br>if(a<=n)<br>sum+=dst(a++);<br>cout<<sum;<br>return 0;<br>}

Answer 1

#include <iostream>
using namespace std;
int dst(int x)
{int y;<br>y=x*x;<br>return y;<br>}
int main ()
{int sum,a=1,n;<br>cin>>n;<br><strong>sum=0;//sum赋初值<br>while(a<=n)//用while循环</strong><br>sum+=dst(a++);<br>cout<<sum;<br>return 0;<br>}

Answer 2

int dst(int x){if(x==1)</p><p> {</p><p> return 1;</p><p> }else{return dst(x-1)+x*x;}}这样才是递归函数。主函数就int main(){int sum,int n;cin>>n;sum=dst(n);cout<<sum;return 0;}