重金悬赏,急!急!,有哪位英语高手帮我翻译这段文字。不要在线翻译,在线翻译我也会,但是有很大误差。

本论文采用共沉淀法,以硫酸镍、硫酸钴、硫酸锰和氢氧化钠为原料,在络合剂氨水的作用下制备得到前驱体,再将前驱体与氢氧化锂以一定摩尔比混合烧结,得到LiNi0.45Co0.1... 本论文采用共沉淀法,以硫酸镍、硫酸钴、硫酸锰和氢氧化钠为原料,在络合剂氨水的作用下制备得到前驱体,再将前驱体与氢氧化锂以一定摩尔比混合烧结,得到LiNi0.45Co0.1Mn0.45O2粉末正极材料。并用X射线衍射仪、激光粒度分布测定仪以及傅立叶红外光谱仪对正极材料进行结构表征,实验结果表明:在原材料摩尔配比Li/(Ni+Co+Mn)为1.05,沉淀剂NaOH浓度为4mol/L,烧成温度为900℃,烧成时间为20h的条件下,所制备的正极材料最佳,并测试该条件下锁制备的正极材料的电化学性能。 展开
 我来答
路人甲_08
2013-05-13
知道答主
回答量:22
采纳率:0%
帮助的人:11.6万
展开全部
This thesis uses the coprecipitation of nickel sulfate, cobalt sulfate, manganese sulfate and sodium hydroxide as raw materials. Precursor is obtained using complexing agent ammonia, then sintered with lithium hydroxide in a fixed molar ratio. LiNi0.45Co0.1Mn0.45O2 powder cathode is obtained. Using the X-ray diffraction, laser particle size distribution analyzer and Fourier transform infrared spectroscopy to examine the structural characterization of the cathode material, experimental results show that in raw materials, the molar ratio of Li / (Ni + Co. + Mn) is 1.05, while the concentration of NaOH, which is used as a precipitating agent, is (-4) mol / L. The temperature needed is 900 ° C and the time needed is 20 hours. Under these conditions, the cathode materials obtained is of good quality.

自翻
已赞过 已踩过<
你对这个回答的评价是?
评论 收起
百度网友c403c16f9
2013-05-13 · TA获得超过3574个赞
知道大有可为答主
回答量:4130
采纳率:33%
帮助的人:1569万
展开全部
In this paper, using co-precipitation method, using nickel sulfate, cobalt sulfate, manganese sulfate and sodium hydroxide as raw material, preparing precursor in complexing agent ammonia effect, then the precursor and lithium hydroxide mixed with a certain ratio to obtain LiNi0.45Co0.1Mn0.45O2 powder sintering, cathode material. And by X ray diffraction, laser granularity distribution tester and Fu Liye infrared spectrometer was used to analyze the structure of cathode materials, the experimental results show that: in the raw material molar ratio of Li/ (Ni+Co+Mn) 1.05, precipitating agent NaOH concentration is 4mol/L, the sintering temperature is 900 ℃, the firing time is 20h, the the best anode material prepared, and the electrochemical performance test conditions under lock the preparation of cathode materials.
本回答被提问者采纳
已赞过 已踩过<
你对这个回答的评价是?
评论 收起
推荐律师服务: 若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询

为你推荐:

下载百度知道APP,抢鲜体验
使用百度知道APP,立即抢鲜体验。你的手机镜头里或许有别人想知道的答案。
扫描二维码下载
×

类别

我们会通过消息、邮箱等方式尽快将举报结果通知您。

说明

0/200

提交
取消

辅 助

模 式