Question

初学者求教：编写一个Shell脚本，实现以下3个功能。

1.Shell脚本运行时需要传入一个参数，该参数用于指定目标路径
2.将目标路径中的所有目录名称输出到/tmp/dir.txt文件中
3.将目标路径中的所有文件名称输出到/tmp/files.txt文件中

Answer 1

可以这样写

#!/bin/bash                                                             
                                                                            
if [ $# -ne 1 ];then                                                    
    echo "Enter your directory"                                         
    exit 1                                                              
fi                                                                      
                                                                            
if [ ! -d $1 ];then                                                     
    echo "Your directory does not exist"                                
    exit 1                                                              
fi                                                                      
                                                                            
ls -l $1 | grep ^d | awk '{print $NF}' > /tmp/dir.txt                   
ls -l $1 | grep ^- | awk '{print $NF}' > /tmp/files.txt                 
                                                                            
echo "Job done"

Answer 2