1/2x-1/x +y(x的平方-y的平方 )(x+ y/2x) 5
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1/2x-1/x +y(x的平方-y的平方 )(x+ y/2x)
1/2x-1/x +y(x^2-y^2)(x+ y/2x)
解,得:
==([1-2)/2x]+y(x+y)(x-y)(x+y)(1/2x)
==-(1/2x)+y(x+y)(x-y)(x+y)(1/2x)
==(1/2x)[y(x+y)(x-y)(x+y)-1]
==(1/2x){y[x^2(x+y)-y^2(x+y)]-1}
==(1/2x){y[(x+y)(x^2-y^2)]-1}
==(1/2x)[y(x+y)(x^2-y^2)-1]
1/2x-1/x +y(x^2-y^2)(x+ y/2x)
解,得:
==([1-2)/2x]+y(x+y)(x-y)(x+y)(1/2x)
==-(1/2x)+y(x+y)(x-y)(x+y)(1/2x)
==(1/2x)[y(x+y)(x-y)(x+y)-1]
==(1/2x){y[x^2(x+y)-y^2(x+y)]-1}
==(1/2x){y[(x+y)(x^2-y^2)]-1}
==(1/2x)[y(x+y)(x^2-y^2)-1]
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