Question

化简：(a/ab-b方-b/a方-ab)除以(1+a方+b方/2ab) Thank you so much!!

急急急！

Answer 1

[a/(ab-b方) -b/(a方-ab)] 除以[1+(a方+b方)/2ab]
={ a/[b(a-b)] - b/[a(a-b)]} 除以 [(2ab+a方+b方)/2ab]
={ (a²-b²)/[ab(a-b)]} × 2ab/（a+b）²
=2/(a+b)

追问

其中a=-1+根号3，b=-1-根号3.

追答

=2/(a+b)
=2/(-1+根号3 -1-根号3)
=2/(-2)
=-1

追问

(2*(a+b))/(1+a^2+b^2)我算出来的