Question

计算：a-1/a²-1+a/a+1；1/m²-m+m-3/m²-1.

最好有详细计算过程，急啊，拜托了

Answer 1

a-1/a²-1+a/a+1；
=（a-1）/(a+1)(a-1) + a/(a+1)
= 1/(a+1) + a/(a+1)
= （1+a）/(a+1)
=1

1/m²-m+m-3/m²-1.
=1/m(m-1) +(m-3)/(m+1)(m-1)
=(m+1+m^2 -3m)/m(m+1)(m-1)
=(m^2-2m+1)/m(m+1)(m-1)
=(m-1)^2/m(m+1)(m-1)
=(m-1)/m(m+1)

【有什么不明白可以继续追问O(∩_∩)O 】
【如果满意，请及时选为满意答案，谢谢】

Answer 2

a-1/a²-1+a/a+1
=(a-1)/(a+1)(a-1)+a/(a+1)
=1/(a+1)+a/(a+1)
=(a+1)/(a+1)
=1;
1/m²-m+m-3/m²-1.
=1/m(m-1)+(m-3)/(m+1)(m-1)
=(m+1+m(m-3))/m(m+1)(m-1)
=(m²-2m+1)/m(m+1)(m-1)
=(m-1)²/m(m+1)(m-1)
=(m-1)/m(m+1);

如果本题有什么不明白可以追问，如果满意记得采纳
如果有其他问题请采纳本题后另发点击向我求助，答题不易，请谅解，谢谢。
祝学习进步

Answer 3

a-1/a²-1+a/a+1
=a-1/(a-1)(a+1)+a/a+1
=1/a+1+a/a+1
=1+a/a+1
=1
1/m²-m+m-3/m²-1.
=1/m(m-1)-m-3/(m-1)(m+1)
=1-m²-3m/m(m-1)(m+1)

Answer 4

(a-1)/(a²-1)+a/(a+1)
=(a-1)/(a-1)(a+1)+a/(a+1)
1/(a+1)+a/(a+1)
=1
1/(m²-m)+(m-3)/(m²-1)
=[(m+1)+m(m-3)]/m(m²-1)
=(m-1)²/m(m²-1)
=(m-1)/m(m+1)