
??? Error: File: C:\MATLAB7\work\matlab.m Line: 1 Column: 1 Missing variable or function是什么意思 5
clearall;clc;conv_poly=[561,753];%卷积吗生成多项式conv_constraints_length=9;%(2,1,9)约束长度是9tre...
clear all;
clc;
conv_poly = [561,753]; %卷积吗生成多项式
conv_constraints_length = 9; %(2,1,9)约束长度是9
trellis = poly2trellis(conv_constraints_length,conv_poly);%产生编码和译码所需的格图
tail = zeros(1,conv_constraints_length-1); %使卷积编码器归零所需比特
tb_len = 50; %回溯长度
N_chip = 12288*2; %一帧的码片数,10ms帧3.84Mchip/s
SF=64; %扩频比为64,即一个编码后的比特变为64个码片
sf_code = zeros(1,SF);
sf_code = Walsh(SF); %这两行代码指定扩频码为[0,1,0,1,0]
%sf_code_anti = 1-2*sf_code; %反极性形式的扩频码
Num_coded_bits = N_chip/SF; %总的编码后的比特数
N_bits = 80; %总原始比特
divisor_CRC=[1 1 0 0 1 1 0 1 1];
Nuser = 3; %用户数,可调整
SNR_db = -21:-13; %仿真的信噪比范围
SNR = 10.^(SNR_db/10); %用自然直表示的信噪比
N_block = 10; %最大仿真数据块个数
ts = 1/(1.2288e6); %码片速率1.2288M
fd = 100; %多普勒频移
tau = [0 ts 2*ts]; %指定为整码片时延
path_position = [0,1,2]; %对应的延迟径位置,度量值为码片
pd = [0 0 0]; %多径平均功率相对值,用dB表示
%产生信道特性
for nu = 1:Nuser %多衰落信道
channel(nu) = rayleighchan(ts,fd,tau,pd);
channel(nu).ResetBeforeFiltering = 1;
channel(nu).StorePathGains = 1;
end 展开
clc;
conv_poly = [561,753]; %卷积吗生成多项式
conv_constraints_length = 9; %(2,1,9)约束长度是9
trellis = poly2trellis(conv_constraints_length,conv_poly);%产生编码和译码所需的格图
tail = zeros(1,conv_constraints_length-1); %使卷积编码器归零所需比特
tb_len = 50; %回溯长度
N_chip = 12288*2; %一帧的码片数,10ms帧3.84Mchip/s
SF=64; %扩频比为64,即一个编码后的比特变为64个码片
sf_code = zeros(1,SF);
sf_code = Walsh(SF); %这两行代码指定扩频码为[0,1,0,1,0]
%sf_code_anti = 1-2*sf_code; %反极性形式的扩频码
Num_coded_bits = N_chip/SF; %总的编码后的比特数
N_bits = 80; %总原始比特
divisor_CRC=[1 1 0 0 1 1 0 1 1];
Nuser = 3; %用户数,可调整
SNR_db = -21:-13; %仿真的信噪比范围
SNR = 10.^(SNR_db/10); %用自然直表示的信噪比
N_block = 10; %最大仿真数据块个数
ts = 1/(1.2288e6); %码片速率1.2288M
fd = 100; %多普勒频移
tau = [0 ts 2*ts]; %指定为整码片时延
path_position = [0,1,2]; %对应的延迟径位置,度量值为码片
pd = [0 0 0]; %多径平均功率相对值,用dB表示
%产生信道特性
for nu = 1:Nuser %多衰落信道
channel(nu) = rayleighchan(ts,fd,tau,pd);
channel(nu).ResetBeforeFiltering = 1;
channel(nu).StorePathGains = 1;
end 展开
2个回答
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询