Question

求一篇用C++编写的复数运算，来实现复数之间的加减乘除操作； 要求自己编写 狂谢...

Answer 1

#include<iostream>
using namespace std;
class Complex
{
double a,b;
public:
Complex(double x,double y);
Complex operator+(Complex &c1);
Complex operator-(Complex &c2);
Complex operator*(Complex &c3);
Complex operator/(Complex &c4);
void shownum(Complex m);
};
Complex::Complex(double x,double y)
{
a=x;
b=y;
}
Complex Complex::operator+(Complex &c1)
{
return Complex(a+c1.a,b+c1.b);
}
Complex Complex::operator-(Complex &c2)
{
return Complex(a-c2.a,b-c2.b);
}
Complex Complex::operator*(Complex &c3)
{
return Complex(a*c3.a,b*c3.b);
}
Complex Complex::operator/(Complex &c4)
{
return Complex(a/c4.a,b/c4.b);
}
void Complex::shownum(Complex m)
{
cout<<m.a<<"+"<<m.b<<"i"<<endl;
}
int main()
{
Complex s(11,12),t(13,14),*p;
p->shownum(s+t);
p->shownum(s-t);
p->shownum(s*t);
p->shownum(s/t);
return 0;
}