求极限!!~~~~
limx→0sin2x/sin5xlimx→0(1-cos2x)/x²limx→0in(1-x/2)^1/xlimx→∞(1+2/x)^2x+1limx→0si...
lim x→0 sin2x/sin5xlim x→0 (1-cos2x)/x²lim x→0 in(1-x/2)^1/xlim x→∞ (1+2/x)^2x+1
lim x→0 sin2x/sin5x
lim x→0 (1-cos2x)/x²
lim x→0 in(1-x/2)^1/x
lim x→∞ (1+2/x)^2x+1
lim x→3 (x-3)cos1/(x-3)
lim x→0 (e^sinx-e^x)/(sinx-x) 展开
lim x→0 sin2x/sin5x
lim x→0 (1-cos2x)/x²
lim x→0 in(1-x/2)^1/x
lim x→∞ (1+2/x)^2x+1
lim x→3 (x-3)cos1/(x-3)
lim x→0 (e^sinx-e^x)/(sinx-x) 展开
展开全部
lim x→0 sin2x/sin5x=lim x→0 2x/5x=2/5
lim x→0 (1-cos2x)/x²=lim x→0 [(4x²)/2]/x²=2
lim x→0 in(1-x/2)^1/x=e^(lim x→0(-x/2·1/x)=e^(-1/2)
lim x→∞ (1+2/x)^2x+1=e^(lim x→∞(2/x·(2x+1))=e^(4)
lim x→3 (x-3)cos1/(x-3)=0 (无穷小和有界函数乘积)lim x→0 (e^sinx-e^x)/(sinx-x)
=lim x→0e^x (e^(sinx-x)-1)/(sinx-x)
=lim x→0 e^x (sinx-x)/(sinx-x)
=e^0
=1
lim x→0 (1-cos2x)/x²=lim x→0 [(4x²)/2]/x²=2
lim x→0 in(1-x/2)^1/x=e^(lim x→0(-x/2·1/x)=e^(-1/2)
lim x→∞ (1+2/x)^2x+1=e^(lim x→∞(2/x·(2x+1))=e^(4)
lim x→3 (x-3)cos1/(x-3)=0 (无穷小和有界函数乘积)lim x→0 (e^sinx-e^x)/(sinx-x)
=lim x→0e^x (e^(sinx-x)-1)/(sinx-x)
=lim x→0 e^x (sinx-x)/(sinx-x)
=e^0
=1
追问
亲爱的,详细解答好不好,我加分。求TAT
追答
够详细了啊。
就应该这样答。
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