急问几道GRE数学题!!!
都是绿皮上的,本人数学不大好,请尽可能详细解释,谢谢!185.20Forwhichofthefollowingpairsofintegersistheleastcommo...
都是绿皮上的,本人数学不大好,请尽可能详细解释,谢谢!
185.20
For which of the following pairs of integers is the least common multiple of the integers minus their greatest common divisor the greatest?
A.3,12 B.5,6 C.10,20 D.11,12 E.15,30
答案:D怎么做?
275.34
If 1 is the greatest common divisor of the
positive integers a and b and if a/b-1=13/8. Then a+b=?
A.11 B 13 C20 D21 E29
答案E怎么做?
158.30
Which of the following cannot be expressed
as the sum of either two or three consecutive positive integer?
A.17 B18 C42 D56 E65
答案D怎么做?
266.17
If n is an integer, then the units digit of
n^2 cannot be?
A0 B2 C4 D5 E6
答案B咋做? 展开
185.20
For which of the following pairs of integers is the least common multiple of the integers minus their greatest common divisor the greatest?
A.3,12 B.5,6 C.10,20 D.11,12 E.15,30
答案:D怎么做?
275.34
If 1 is the greatest common divisor of the
positive integers a and b and if a/b-1=13/8. Then a+b=?
A.11 B 13 C20 D21 E29
答案E怎么做?
158.30
Which of the following cannot be expressed
as the sum of either two or three consecutive positive integer?
A.17 B18 C42 D56 E65
答案D怎么做?
266.17
If n is an integer, then the units digit of
n^2 cannot be?
A0 B2 C4 D5 E6
答案B咋做? 展开
1个回答
展开全部
1\下面哪组整数的最小公倍数渐趋最大公约数的值最大?
2、如果1是a和b的最大公约数,并如果a/b-1=13/8,。。。
从a/b-1=13/8得出a/b=21/8,又因为1是a和b的最大公约数,所以a=21,b=8.所以a+b=29
3、下面哪个不能表示连续2或3哥正整数的和。
17=8+9,18=5+6+7,42=13+14+15,65=32+33
4、如果n是整数,那么n^2的个位数不会是哪个?
你把0到9都想一遍,只有2不是
2、如果1是a和b的最大公约数,并如果a/b-1=13/8,。。。
从a/b-1=13/8得出a/b=21/8,又因为1是a和b的最大公约数,所以a=21,b=8.所以a+b=29
3、下面哪个不能表示连续2或3哥正整数的和。
17=8+9,18=5+6+7,42=13+14+15,65=32+33
4、如果n是整数,那么n^2的个位数不会是哪个?
你把0到9都想一遍,只有2不是
追问
第3题是怎么试出来的?比如怎么知道42=13+14+15的?怎么一下子想到的?
第4题:n等于多少,n^2个位数是5和6?
追答
3、如果是奇数就除以2,比如17/2=8.5,就是8+9,偶数就除以3,中间数加上前一个和后一个。42/3=14,所以42=13+14+15
4、5^2=25,6^2=36这两个满足个位是5和6啊~
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