已知xy=-2,x-y=3,求(x+y)(x-y)-y^2+(x-y)^2-(6x^2y-2xy^2)/(2y)=?
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2013-11-06
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(x+y)(x-y)-y^2+(x-y)^2-(6x^2y-2xy^2)/(2y)
=X^2-y^2-y^2+X^2+y^2-2xy-3x^2+xy
=-x^2-y^2-xy
=-(x^2+y^2+xy-3xy+3xy)
=-(x-y)^2-3xy
=-9+6
=-3
=X^2-y^2-y^2+X^2+y^2-2xy-3x^2+xy
=-x^2-y^2-xy
=-(x^2+y^2+xy-3xy+3xy)
=-(x-y)^2-3xy
=-9+6
=-3
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