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2个回答
2014-10-04
展开全部
(1)代入三个点的坐标 ,得到方程组:
a - b + c = 0
9a + 3b + c = 0
0 + 0 + c = 3
∴a = -1 ,b = 2 ,c = 3
抛物线解析式:y = -x^2 + 2x + 3
y = -x^2 + 2x + 3 = -(x - 1)^2 + 4
(2)∴顶点为: D(1 ,4) ,连接OD
则:S(ABDC) = S(AOC) + S(OCD) + S(BOD)
= 1·3/2 + 3·1/2 + 3·4/2
= 9
a - b + c = 0
9a + 3b + c = 0
0 + 0 + c = 3
∴a = -1 ,b = 2 ,c = 3
抛物线解析式:y = -x^2 + 2x + 3
y = -x^2 + 2x + 3 = -(x - 1)^2 + 4
(2)∴顶点为: D(1 ,4) ,连接OD
则:S(ABDC) = S(AOC) + S(OCD) + S(BOD)
= 1·3/2 + 3·1/2 + 3·4/2
= 9
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