Question

若偶函数y=f（x）是最小正周期为2的周期函数，且当2≤x≤3时f（X）=X，则当-2≤x≤0时f（x）的解析式为__

要详细解答，越详细越好。谢谢。

Answer 1

f(x)=x [2,3]
f(x)=x [0,1]
f(x)=-x [-1,0]
f(x)=-x [1,2]
所以
f(x)=x [-2,-1]
f(x)=-x [-1,0]

追问

答案给的是f(x）=｛4+x,-2≤x≤1；2-x,-1<x≤0

追答

f(x)=x [2,3]
f(x)=x+2 [0,1]
f(x)=-x+2 [-1,0]
f(x)=-x+4 [1,2]
所以
f(x)=x+4 [-2,-1]
f(x)=-x+2 [-1,0]