Question

计算：（a²-4/a²-4a+4-2/a-2）÷a²+2a/a-2;(x²-1/x²-2x+1+1-x/x+1)÷x/x-1.

最好有计算过程，急急急

Answer 1

1、原式=[(a+2)/(a-2)-2/(a-2)]÷(a²+2a)/(a-2)=a/(a-2)*(a-2)/(a²+2a)=1/(a+2)
2、原式=[（x+1）/（x-1）+（1-x）/（x+1）]÷x/（x-1）=4x/（x^2-1）÷x/(x-1)=4/(x+1)