Question

初一数学分解因式

Answer 1

Answer 2

1、x的(2n+1)次方(a²-b²x²)
=x的(2n+1)次方(a+bx)(a-bx)

2、(x²-4x+4)²
=(x-2)的4次方

3、x(x+y)(x-y-x-y)
=-2xy(x+y)

4、9m²-n²-6m+2n
=(3m+n)(3m-n)-2(3m-n)
=(3m-n)(3m+n-2)

5、[3(x-y)-2(x+y)]²
= (x-5y)²

Answer 3

1、x的(2n+1)次方(a²-b²x²)
=x的(2n+1)次方(a+bx)(a-bx)

2、(x²-4x+4)²
=(x-2)的4次方

3、x(x+y)(x-y-x-y)
=-2xy(x+y)

4、9m²-n²-6m+2n
=(3m+n)(3m-n)-2(3m-n)
=(3m-n)(3m+n-2)

5、[3(x-y)-2(x+y)]²
= (x-5y)²

Answer 4

(1)原式=(a^2-b^2*x^2)x^(2n+1)=(a+bx)(a-bx)*x^(2n+1)
(2)原式=(x^2-4x+4)^2=(x-2)^4
(3)原式=x(x+y)(x-y-x-y)=-2xy(x+y)
(4)原式=(3m-1)^2-(1-n)^2=(3m-1-1+n)(3m-1+1-n)=(3m+n-2)(3m-n)
(5)原式=[3(x-y)-2(x+y)]^2=(x-5y)^2

Answer 5

(1)原式=(a^2-b^2*x^2)x^(2n+1)=(a+bx)(a-bx)*x^(2n+1)
(2)原式=(x^2-4x+4)^2=(x-2)^4
(3)原式=x(x+y)(x-y-x-y)=-2xy(x+y)
(4)原式=(3m-1)^2-(1-n)^2=(3m-1-1+n)(3m-1+1-n)=(3m+n-2)(3m-n)
(5)原式=[3(x-y)-2(x+y)]^2=(x-5y)^2