Question

绝对路径删除部分前缀，咋弄，c语言

D:\\1\\2\\3.txt 现在想弄成2\\3.txt

Answer 1

#include<string.h>
#include<stdio.h>
int main(void)
{
char spre1[]="c:\\abc\\abcde\\";
char spre2[]="c:\\abc\\";
char mypath[]="c:\\abc\\abcde\\abcde\\abc.txt";
char newpath[80];
strcpy(newpath,mypath+strlen(spre1));
printf("spre: %s\nmypath: %s\nnewpath: %s\n",spre1,mypath,newpath);
strcpy(newpath,mypath+strlen(spre2));
printf("spre: %s\nmypath: %s\nnewpath: %s\n",spre2,mypath,newpath);
return 0;
}
不知道对你是否有帮助..

Answer 2

char* old_path = "D:\\1\\2\\3.txt";
char* new_path = old_path;
while(new_path) {
if (*new_path == '2')
break;
new_path++;
}

追问

一大批的字符呐 比如还有D:\\1\\ABC\\789.doc

追答

char* old_path = "D:\\1\\2\\3.txt";
char* new_path = old_path;
while(new_path) {
if (*new_path == '\\') {
char input;
printf("%s是否为您需要的路径，y or n?\n", new_path);
gets(&input);
if (input == 'y' || input == 'Y') {
break;
}
}
new_path++;
}
new_path++;