1个回答
2013-05-29
展开全部
移相,把2an移到右边得
an平方-an-1平方-an-an-1=0
(an-an-1)(an+an-1)-(an+an-1)=0
(an-an-1-1)(an+an-1)=0
an>0,所以an+an-1>0
所以an-an-1-1=0
所以an-an-1=1
an平方-an-1平方-an-an-1=0
(an-an-1)(an+an-1)-(an+an-1)=0
(an-an-1-1)(an+an-1)=0
an>0,所以an+an-1>0
所以an-an-1-1=0
所以an-an-1=1
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