Question

数学题，给好评，谢谢

Answer 1

1. x²+（√2+√3）x+√6=0

     （x+√2）（x+√3）=0

                       x1=-√2；x2=-√3

2. （x+3）（x-1）=5

            x²+2x-3-5=0

               x²+2x-8=0

   （x-2）（x+4）=0

                   x1=2；x2=-4

3. （2x+1）²+3（2x+1）+2=0

            4x²+4x+1+6x+3+2=0

                         4x²+10x+6=0

              （x+1）（4x+6）=0

                               x1=-1；x2=-1.5

Answer 2

x²+(√2+√3)x+√6=0
（x+√2)(x+√3)=0
x+√2=0 x+√3=0
∴
x1=-√2
x2=-√3

(x+3)(x-1)=5
x²+2x-3-5=0
x²+2x-8=0
(x-2)(x+4)=0
x-2=0 x+4=0
∴
x1=2
x2=-4

(2x+1)²+3(2x+1）+2=0
(2x+1+1)(2x+1+2)=0
(2x+2)(2x+3)=0
2x+2=0 2x+3=0
∴
x1=-1
x2=-1.5